Draw a velocity-time graph from the data given below: a) What type of motion is represented during 0-6 second? b) What is the acceleration in the first 6 seconds? c) Using graph, calculate the distance travelled between 6 to 8 seconds. d) Calculate retardation during 12-14 seconds
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2.2.5m/s^2
3.dist travel = area covered
= ar. of trapezium formed = 35 m
4.5m/s^2
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hey dude i just want to correct a small error
The last answer is not 5 metre per second square..... it is negative 5 metre per second square
Since final velocity is less than initial velocity and
a= (v-u ) ÷ t