Answer:
3)
Explanation:
2A+B--->1/2C
from the rate of reaction law
(1/2)*d[A]/dt=(1/1)*d[B]/dt={1/(1/2)}*d[C]/dt
d[A]/dt=2*10^-2
(1/2)*(2*10^-2)=2*d[C]/dt
d[C]/dt=1/2*10^-2
=0.5*10^-2Ms-1
d[C]/dt=5*10^-3
rate of reaction=(1/2)*2*10^-2
=10^-2Ms-1
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Answers & Comments
Answer:
3)
Explanation:
2A+B--->1/2C
from the rate of reaction law
(1/2)*d[A]/dt=(1/1)*d[B]/dt={1/(1/2)}*d[C]/dt
d[A]/dt=2*10^-2
(1/2)*(2*10^-2)=2*d[C]/dt
d[C]/dt=1/2*10^-2
=0.5*10^-2Ms-1
d[C]/dt=5*10^-3
rate of reaction=(1/2)*2*10^-2
=10^-2Ms-1