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So a conical tent accomodates 11 persons and each person must have 4 m^2 of the space so the area of the base of the tent is (11×4)=44m^2 imagine the radius of the base is r m so, πr^2=44 or, r^2=44× 7/22 or r= √14 m on the ground 20 m^3 air is applicable for each 11 persons so the volume of the tent should be = (20×11)m^3=220m^3 imagine the height is h m so the volume of the tent is = [π × (√14)^2 × h] m^3 = 22/7 × 14 × h m^3 so,
22/7 ×14×h=220 or, 44h=220 or, h=5 m so the height of the tent is 5 m (Answer) Hope it helps,pls mark the answer as brainliest.
Answers & Comments
so the area of the base of the tent is (11×4)=44m^2
imagine the radius of the base is r m
so,
πr^2=44
or, r^2=44× 7/22
or r= √14 m
on the ground 20 m^3 air is applicable for each 11 persons
so the volume of the tent should be
= (20×11)m^3=220m^3
imagine the height is h m
so the volume of the tent is = [π × (√14)^2 × h] m^3
= 22/7 × 14 × h m^3
so,
22/7 ×14×h=220
or, 44h=220
or, h=5 m
so the height of the tent is 5 m (Answer)
Hope it helps,pls mark the answer as brainliest.