Answer:
The first trinomial
x2+7x+12
is in the form of
ax2+bx+c,
We have to find two integers whose sum is 7 and the product is 12,
By trial, we see that
3+4=7 and 3⋅4=12.
Explanation
The trinomial is in the form
ax2+bx+c
, where a, b and c are integers.
Therefore, split b (the coefficients of x) into two parts such that the algebraic sum of these two parts is b and their product is ac.
If x is a literal coefficients and m, n are positive integers, then
xm÷xn=xm−n, when mn.
Step-by-step explanation:
Hope its help
#CarryOnLearning
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Answers & Comments
Answer:
The first trinomial
x2+7x+12
is in the form of
ax2+bx+c,
We have to find two integers whose sum is 7 and the product is 12,
By trial, we see that
3+4=7 and 3⋅4=12.
Explanation
The trinomial is in the form
ax2+bx+c
, where a, b and c are integers.
Therefore, split b (the coefficients of x) into two parts such that the algebraic sum of these two parts is b and their product is ac.
If x is a literal coefficients and m, n are positive integers, then
xm÷xn=xm−n, when mn.
Step-by-step explanation:
Hope its help
#CarryOnLearning