Answer:
To divide the polynomial 6x^3 - 7x^2 - 16x^2 + 12 by 2x + 3, you can use long division. Here's how you can do it:
```
3x^2 - 2x + 4
______________________
2x + 3 | 6x^3 - 7x^2 - 16x^2 + 12
- (6x^3 + 9x^2)
-16x^2 + 12
- (-16x^2 - 24x)
36x + 12
- (36x + 54)
-42
So, when you divide 6x^3 - 7x^2 - 16x^2 + 12 by 2x + 3, the quotient is 3x^2 - 2x + 4, and the remainder is -42.
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Answers & Comments
Answer:
To divide the polynomial 6x^3 - 7x^2 - 16x^2 + 12 by 2x + 3, you can use long division. Here's how you can do it:
```
3x^2 - 2x + 4
______________________
2x + 3 | 6x^3 - 7x^2 - 16x^2 + 12
- (6x^3 + 9x^2)
______________________
-16x^2 + 12
- (-16x^2 - 24x)
______________________
36x + 12
- (36x + 54)
______________________
-42
```
So, when you divide 6x^3 - 7x^2 - 16x^2 + 12 by 2x + 3, the quotient is 3x^2 - 2x + 4, and the remainder is -42.