Divide ×³+3×²-7×+15 by ×+5.A.×²+2×+3B.×²-2×+3C.×²-2×-3D.×²+2×-3. Created by christinelorismarcel. Math

Answer:B. x² - 2x + 3Step-by-step explanation:We can solve it by simplifying or by long division, but from now i will solve it by simplifying the expression.If you want me to solve it using long division just request it in the comments section and i will do it.Therefore, the answer is x² - 2x + 3.#CarryOnLearning

Divide ×³+3×²-7×+15 by ×+5.A.×²+2×+3B.×²-2×+3C.×²-2×-3D.×²+2×-3...

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christinelorismarcel @christinelorismarcel

October 2022 2 1 Report

Divide ×³+3×²-7×+15 by ×+5.
A.×²+2×+3
B.×²-2×+3
C.×²-2×-3
D.×²+2×-3

MaximoRykei

Verified answer

Answer:

B. x² - 2x + 3

Step-by-step explanation:

We can solve it by simplifying or by long division, but from now i will solve it by simplifying the expression.

If you want me to solve it using long division just request it in the comments section and i will do it.

$\tt \: \dfrac{x {}^{3} + 3x {}^{2} - 7x + 15 }{x + 5} \\ \\ \tt \: = \dfrac{x {}^{3} + 5x {}^{2} - 2x {}^{2} - 10x + 3x + 15 }{x + 5} \\ \\ \tt \: = \dfrac{x {}^{2}(x + 5) - 2x(x + 5) + 3(x + 5) }{x + 5} \\ \\ \tt \: = \dfrac{(x + 5)(x {}^{2} - 2x + 3) }{x + 5} \\ \\ \tt \: = \dfrac{ \cancel{(x + 5)}(x {}^{2} - 2x + 3) }{ \cancel{x + 5}} \\ \\ \tt \orange{ = x {}^{2} - 2x + 3}$

Therefore, the answer is x² - 2x + 3.

#CarryOnLearning

leximontefalco02 mali yan bichh

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