Answer:
Explanation:
According to the Question
It is given that,
we have to calculate distance covered by a freely falling body during the first three second of its motion.
Acceleration due to gravity is 10m/s².
So, here the initial velocity will be 0 m/s.
Now, using Kinematic Equation
by substituting the value we get
⇢ s = 0 × 3 + ½ × 10 × 3²
⇢ s = 0 + 5 × 9
⇢ s = 45 m
45 m is the required answer .
Time taken ,t = 3s
s = ut + ½ gt²
Hence, the distance covered by the body is 45 metres .
[tex]answer}[/tex]
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Verified answer
Answer:
Explanation:
According to the Question
It is given that,
we have to calculate distance covered by a freely falling body during the first three second of its motion.
Acceleration due to gravity is 10m/s².
So, here the initial velocity will be 0 m/s.
Now, using Kinematic Equation
by substituting the value we get
⇢ s = 0 × 3 + ½ × 10 × 3²
⇢ s = 0 + 5 × 9
⇢ s = 45 m
Explanation:
Answer:
45 m is the required answer .
Explanation:
According to the Question
It is given that,
Time taken ,t = 3s
we have to calculate distance covered by a freely falling body during the first three second of its motion.
Acceleration due to gravity is 10m/s².
So, here the initial velocity will be 0 m/s.
Now, using Kinematic Equation
s = ut + ½ gt²
by substituting the value we get
⇢ s = 0 × 3 + ½ × 10 × 3²
⇢ s = 0 + 5 × 9
⇢ s = 45 m
Hence, the distance covered by the body is 45 metres .
[tex]answer}[/tex]