Directions : Solve the following problem.
1. A rectangular table has an area of 192 sq. m. with a length of 16 m. What is the measures of its width? Find the perimeter of the table.
A = lw
P = 21 + 2w or 2(1+w)
2. One side of a triangular flower garden has a length of 4.5 m, the second side is twice as long as the first side. The length of the third side is 3 m less than that of the second side. What is the perimeter of the garden?
P = s + s + s
p.s BRAINLIEST MAAYOS NA SAGOT, READ THE DIRECTIONS CAREFULLY. NONSENSICAL ANSWERS WILL AUTOMATICALLY REPORT.
Answers & Comments
Answer:
1. A rectangular table has an area of 192 sq. m. with a length of 16 m. What is the measures of its width? Find the perimeter of the table.
Using the formula for finding the width:![w=\frac{A}{l} w=\frac{A}{l}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7BA%7D%7Bl%7D)
The perimeter:
2. One side of a triangular flower garden has a length of 4.5 m, the second side is twice as long as the first side. The length of the third side is 3 m less than that of the second side. What is the perimeter of the garden?
2nd side: Twice of First Side
2nd Side: 2 (4.5 m)
2nd Side: 9
3rd Side: 3 m less than of 2nd side
3rd Side: 9 - 3
3rd Side: 6
Perimeter: 4.5 + 9 + 6 = 19.5 m