1.)
S = 2(3.14×4cm)
S = 2(12.56)
S = 25.12cm
2.)
S = 2(3cm)²(4cm)
S = 2 (6cm × 4cm)
S = 2(24cm)
S = 48cm
3.)
S = 2(2mm)²(7mm)
S = 2(4mm × 7mm)
S = 2(28mm)
S = 56mm
Answer:
1 nasa taas po
2What is the total surface area of the cone that has a base radius of 3 cm and height of 4 cm?
The area of the base is A = πr²
The area of the curved surface of a regular cone is A = ½·2·π·r·s = π·r·s where s = slant height.
The slant height is s = √(r² + h²) = √(3² + 4²) = √(25) = 5
Base = π(3)² = 9π
Curved A = π·3·5 = 15π
24π cm² is the total surface area of the closed right cone or about 75.398 cm²
3 Therefore, radius of cylinder is 3.502cm
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Answers & Comments
1.)
S = 2(3.14×4cm)
S = 2(12.56)
S = 25.12cm
2.)
S = 2(3cm)²(4cm)
S = 2 (6cm × 4cm)
S = 2(24cm)
S = 48cm
3.)
S = 2(2mm)²(7mm)
S = 2(4mm × 7mm)
S = 2(28mm)
S = 56mm
#CarryOnLearning
Answer:
1 nasa taas po
2What is the total surface area of the cone that has a base radius of 3 cm and height of 4 cm?
The area of the base is A = πr²
The area of the curved surface of a regular cone is A = ½·2·π·r·s = π·r·s where s = slant height.
The slant height is s = √(r² + h²) = √(3² + 4²) = √(25) = 5
Base = π(3)² = 9π
Curved A = π·3·5 = 15π
24π cm² is the total surface area of the closed right cone or about 75.398 cm²
3 Therefore, radius of cylinder is 3.502cm