Directions: Determine the nth term of each sequence, then give the pattern rule
1. 16, 25, 36, 49
2. 48, 44, 40, 36
3. 5, 11, 17, 23
4. 3, 6, 12, 24, 48
5. 43, 38, 33, 28
1. 16, 25, 36, 49
2. 48, 44, 40, 36
3. 5, 11, 17, 23
4. 3, 6, 12, 24, 48
5. 43, 38, 33, 28
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Answer:
See.. there are two solution for this question…
First one:—
(1×1)=1
(2×2)=4
(3×3)=9
(4×4)=16
(5×5)=25
(6×6)=36
(7×7)=49
(8×8)=64
(9×9)=81
(10×10)=100…. So as you saw that the pattern above is the square of consecutive numbers from 1 to 7… nd the rest are the square of 8..9 nd 10…
Bow second method…
The series above is…
1…4…9…16…25…36…49
Here…
4-1=3
9-4=5
16-9=7
25-16=9
36-25=11
49-36=13…
So u can see that the difference between each term is a prime number ….and they form a series itself…
Series of odd no…..u can call it in Airthmetic progression too…
3..5..7..9..11..13.. nd the next odd no. Are 15..17 nd 19….
So the next 3 no. In the pattern are…
49+15=64
64+17=81
81+19=100