Dion moving with an initial velocity of 40 m/s, stops after a displacement of 120m on application of brakes. We are required to find dion's deceleration and the time taken to stop dion.
Step-by-step explanation: #Carryonlearning :)
Initial velocity (u) of the car = 40 m/s
Final velocity of the car (v) = 0 m/s
Displacement of car before stopping (s) = 120 m.
Using the relation: v² - u² = 2 a s
0² - 40² = 2× a × 120; ==> a = - 40²/(2×120) =-(20/3) m/s²
The acceleration of the car =-20/3 m/s² = - 6.666 m/s² ( negative sign signifies deceleration).
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Answer:
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Dion moving with an initial velocity of 40 m/s, stops after a displacement of 120m on application of brakes. We are required to find dion's deceleration and the time taken to stop dion.
Step-by-step explanation:
#Carryonlearning :)
Initial velocity (u) of the car = 40 m/s
Final velocity of the car (v) = 0 m/s
Displacement of car before stopping (s) = 120 m.
Using the relation: v² - u² = 2 a s
0² - 40² = 2× a × 120; ==> a = - 40²/(2×120) =-(20/3) m/s²
The acceleration of the car =-20/3 m/s² = - 6.666 m/s² ( negative sign signifies deceleration).
We can find time taken using: v = u + a t
So time t taken to stop the car.
0 = 40 - (20/3)× t ; ==> t = 40×3/20 =6 s.