Answer:Length of painted cardboard=8 cm and breadth of painted card =5cm
Since, there is a margin of 1.5cm long from each of its side.
Therefore reduced length
=8−(1.5+1.5)=8−3=5cm
And reduced breadth
=5−(1.5+1.5)=5−3=2cm
∴ Area of margin=Area of cardboard(ABCD)−Area of cardboard(EFGH)
=(AB×AD)−(EF×EH)
=(8×5)−(5×2)
=40−10
=30cm 2
Thus, the total area of margin is 30cm2
Step-by-step explanation:
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Answer:Length of painted cardboard=8 cm and breadth of painted card =5cm
Since, there is a margin of 1.5cm long from each of its side.
Therefore reduced length
=8−(1.5+1.5)=8−3=5cm
And reduced breadth
=5−(1.5+1.5)=5−3=2cm
∴ Area of margin=Area of cardboard(ABCD)−Area of cardboard(EFGH)
=(AB×AD)−(EF×EH)
=(8×5)−(5×2)
=40−10
=30cm 2
Thus, the total area of margin is 30cm2
Step-by-step explanation: