Answer:
Let y=log(logx),x>1
So,
dx
dy
=
logx
1
d
(logx)
.
x
By the chain rule
Step-by-step explanation:
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Answers & Comments
Answer:
Let y=log(logx),x>1
So,
dx
dy
=
logx
1
dx
d
(logx)
dx
dy
=
logx
1
.
x
1
By the chain rule
Step-by-step explanation:
Let y=log(logx),x>1
So,
dx
dy
=
logx
1
dx
d
(logx)
dx
dy
=
logx
1
.
x
1