Answer:
afternoon Radius of the roller (r)=
2
84
cm=42cm
length of the roller (h)=120cm
∴ Area of the playground levelled in taking 1 complete revolution 2πrh
=2×227×42×120=31680cm
∴ Area of the playground
=31680×500=15840000cm
100×100
15840000
m
=1584m
I hope this helps ✌️
Please mark as brilliant answer
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Verified answer
Answer:
afternoon Radius of the roller (r)=
2
84
cm=42cm
length of the roller (h)=120cm
∴ Area of the playground levelled in taking 1 complete revolution 2πrh
=2×227×42×120=31680cm
2
∴ Area of the playground
=31680×500=15840000cm
2
100×100
15840000
m
2
=1584m
2
Answer:
I hope this helps ✌️
Please mark as brilliant answer