Verified answer

R={(x,y): y=x+5 and x<4} = {(1,6),(2,7),(3,8)}

Reflexive :

It is seen that (1,1) doesn't belong to R

∴R is not reflexive.

Symmetric :

Also (1,6) ∈ R

But, (1,6) doesn't belong to R

∴R is not symmetric.

Transitive :

Now, there is no pair in R such that (x,y) and (y,z) ∈ R, then (x,z) cannot belong to R.

∴R is transitive.

Hence, R is neither reflexive, nor symmetric, but transitive.

Answer:

R={(x,y):y=x+5andx<4}={(1,6),(2,7),(3,8)}

It is seen that (1,1)∈

/

R⇒R is not reflexive.

Also (1,6)∈R.

But, (1,6)∈

/

R. ∴R is not symmetric.

Now, since there is no pair in R such that (x,y) and (y,z)∈R, then (x,z) cannot belong to R.

∴R is transitive.

Hence, R is neither reflexive, nor symmetric, but transitive.

Step-by-step explanation:

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