Determine whether each ordered pair is a solution to the inequality 2x + 3y > 2

Answer:

a. (1,1) → TRUE

b. (4,-3) → FALSE

c. (-8,12)​ → TRUE

Solution:

#BY SUBSTITUTION#

a. (1,1)

#If x = 1 then y = 1#

→ 2x + 3y > 2

→ 2(1) + 3(1) > 2

→ (2) + (3) > 2

→ 5 > 2 (This statement is True)

b. (4,-3)

#If x = 4 then y = -3#

→ 2x + 3y > 2

→ 2(4) + 3(-3) > 2

→ (8) + (-9) > 2

→ -1 > 2 (This statement is False)

c. (-8,12)​

#If x = 8 then y = -12#

→ 2x + 3y > 2

→ 2(-8) + 3(12) > 2

→ (-16) + (36) > 2

→ 20 > 2 (This statement is True)

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