Determine the empirical formula of a compound whose percentage composition is 50.05% S and 49.95% O by mass. Guide Questions 1. What are the elements involved in the sample problem? 2. What will be solved in this problem? 3. What is empirical formula?
Answers & Comments
Answer:
1. Sulfur (S) and Oxygen (O)
2. empirical formula (mole ratio)
3. or Sulfur Dioxide
Solution:
G: 50.05% S ; 49.95%O
R: empirical formula
A: find the mole ratio
S:
assume 100g:
50.05% S = 50.05g S
49.95% O = 49.95g O
convert from mass to moles:
solve for mole ratio:
*1.5605mol is the lowest amongst the moles so use it as the divisor
use the mole ratio to write the formula:
A: The empirical formula is
more commonly known as sulfur dioxide