Answer:

the following is just an example so that you can understand and solve it by yourself

Step-by-step explanation:

We need to prove the points (3,-2),(5,2) and(8,8) are collinear.

A=(3,-2) B=(5,2) C=(8,8)

Let The points B divides AC in the ratio of k:1.

Then the coordinates will be,

Coordinates of B are (5,2)

Comparing we get,

Value of k is same in both.

Therefore Points A,B,C are collinears.

Answer:

Yes these points are collinear.

Step-by-step explanation:

Here, x1 = (-4),x2 =0 ,x3 = 2,y1 = 3,y2 = 3 and y3 = 3

If all points are collinear

Then the area of the triangle formed is 0 as height is 0

According to area of triangle formula,

½[x1(y2-y3) + x2(y3-y1) + x3(y1-y2) ]

as all the y1, y2 and y3 are vauled as 3

so y1-y2 = 0 , y3-y1 = 0 and y2-y3= 0

½[x1(0) +x2(0) +x3(0) ]

½[ 0+0+0)]

½(0) = 0

since it is satisfying the condition of having area of triangle 0

Hence, all the points are collinear