For small temperature difference between a body and its surrounding, the rate of cooling of the body is directly proportional to the temperature difference and the surface area exposed. dQ/dt ∝ (q – qs)], where q and qs are temperature corresponding to object and surroundings.
For small temperature difference between a body and its surrounding, the rate of cooling of the body is directly proportional to the temperature difference and the surface area exposed. dQ/dt ∝ (q – qs)], where q and qs are temperature corresponding to object and surroundings.
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Answer:
Law of Cooling Derivation
For small temperature difference between a body and its surrounding, the rate of cooling of the body is directly proportional to the temperature difference and the surface area exposed. dQ/dt ∝ (q – qs)], where q and qs are temperature corresponding to object and surroundings.
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For small temperature difference between a body and its surrounding, the rate of cooling of the body is directly proportional to the temperature difference and the surface area exposed. dQ/dt ∝ (q – qs)], where q and qs are temperature corresponding to object and surroundings.
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