SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & P_{\text{N}_2} = \text{1755 psi} \\ & P_{\text{Ar}} = \text{22 psi} \\ & P_{\text{T}} = \text{2250 psi} \end{aligned}[/tex]

Step 2: Calculate the partial pressure of O₂ by using Dalton's law of partial pressures.

[tex]\begin{aligned} P_{\text{T}} & = P_{\text{N}_2} + P_{\text{Ar}} + P_{\text{O}_2} \\ P_{\text{O}_2} & = P_{\text{T}} - P_{\text{N}_2} - P_{\text{Ar}} \\ & = \text{2250 psi} - \text{1755 psi} - \text{22 psi} \\ & = \boxed{\text{473 psi}} \end{aligned}[/tex]

Hence, the partial pressure of oxygen gas in the tank is 473 psi.

[tex]\\[/tex]

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