Dear friends i need ur help -*the sum of the digits of a two dist no. is 9,if the digits r reversed,the no. is 63 more than the original. Find the number.(plz answer fast as u can)
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Given that the sum of the digits is equal to 9.
Therefore
x + y = 9. (Equation 1)
Also given that if the digits are reversed then the number is 36 more than the original number
Therefore
10y + x = 10x + y + 63
9x - 9y = - 63
Taking 9 as common
x - y = - 7 (Equation 2)
Adding equation 1 and 2
x + y = 9
x - y = - 7
2x = 2
x = 1
2 + y = 9
y = 7
Therefore the number is 10x + y = 10(1) + 7 = 17
Hope this helps you.