De Morgan’s law that :A. (AB)’= A’ + B’ B. (A+B)’ A’ *BC. A’ + B’=A’B’ D. (AB)’=A’ + B. Created by ayush002275.

De Morgan’s law that :A. (AB)’= A’ + B’ B. (A+B)’ A’ *BC. A’ + B’=A’B’ D. (AB)’=A’ + B

Questions

ayush002275 @ayush002275

June 2023 1 5 Report

De Morgan’s law that :

A. (AB)’= A’ + B’ B. (A+B)’ A’ *B

C. A’ + B’=A’B’ D. (AB)’=A’ + B

Answers & Comments

ladriya52

Answer:

The sum of a variable and its complement is 1 and their product is 0 — A+A'=1 and A.A'=0. The theorem states that A'.B' is the complement of A+B. To prove, it must satisfy:

(A + B)(A' . B') = 0 and

(A + B) + (A' . B') = 1

Consider the first case:

(A + B)(A' . B') = 0

Second Case:

(A + B) + (A' . B') = 1

Add an Answer

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Answers & Comments

(A + B)(A' . B') = 0 and

(A + B) + (A' . B') = 1

Consider the first case:

(A + B)(A' . B') = 0

Second Case:

(A + B) + (A' . B') = 1

Add an Answer

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