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Class 10

>>Maths

>>Quadratic Equations

>>Nature of Roots

>>Find the value(s) of k if the equation (

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Find the value(s) of k if the equation (k+1)x

2

−2(k−1)x+1=0 has real and equal roots.

This question has multiple correct options

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Solution

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Correct options are A) and C)

The given equation is

(k+1)x

2

−2(k−1)x+1=0

comparing it with ax

2

+bx+c=0 we get

a=(k+1),b=−2(k−1) and c=1

∴ Discriminant,

D=b

2

−4ac=4(k−1)

2

−4(k+1)×1

=4(k

2

−2k+1)−4k−4

⇒4k

2

−8k+4−4k−4=4k

2

−12k

Since roots are real and equal, so

D=0⇒4k

2

−12k=0⇒4k(k−3)=0

⇒ either k=0 or k−3=0⇒4k(k−3)=0

Hence, k=0,3.

Answer:

k-l)²+(l-2)² = 0

k^l +l^k =mol^-1

R= 8.314 J K^-1

1.6 x 10^6 s^-1

Ea= 0

k-l)²+(l-2)² = 0

k^l +l^k