trig identities quiz
1.) 2 cos θtan θcsc θ=2
2.) 6 cos θ( 1/cos θ - cot θ/cscθ) =6 sin² θ
1.) 2 cos θtan θcsc θ=2
2.) 6 cos θ( 1/cos θ - cot θ/cscθ) =6 sin² θ
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Answer:
1.
2cosθtanθcscθ = 2
cosθ(sinθ/cosθ)(1/sinθ) = 1
1 = 1
2.
6cosθ(1/cosθ - cotθ/cscθ) = 6sin²θ
cosθ (1/cosθ -
/
) = sin²θ
cosθ(1/cosθ - cosθ) = sin²θ
1 - cos²θ = sin²θ
sin²θ = sin²θ