Answer:
.................,..................................
Taking LHS=cot
2
θ−cos
θ=
sin
θ
cos
−cos
θ[∵cotθ=
sinθ
cosθ
]
=
θ−sin
θcos
θ(1−sin
θ)
[∵cos
θ+sin
θ=1]
=cot
θ=RHS
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
.................,..................................
Verified answer
Answer:
Taking LHS=cot
2
θ−cos
2
θ=
sin
2
θ
cos
2
θ
−cos
2
θ[∵cotθ=
sinθ
cosθ
]
=
sin
2
θ
cos
2
θ−sin
2
θcos
2
θ
=
sin
2
θ
cos
2
θ(1−sin
2
θ)
[∵cos
2
θ+sin
2
θ=1]
=
sin
2
θ
cos
2
θcos
2
θ
=cot
2
θcos
2
θ=RHS