Answer:
Let point P(0,y) is on the y-axis, then
PA=PB
or PA
2
=PB
(6−0)
+(5−y)
=(−4−0)
+(3−y)
36+25−10y+y
=16+9−6y+y
61−10y+25−6y
61−25=−6y+10y
36=4y
or y=9
The required point is (0,9).
Step-by-step explanation:
Actually I am study for my exam of half early they will going to began that's why
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Verified answer
Answer:
Let point P(0,y) is on the y-axis, then
PA=PB
or PA
2
=PB
2
(6−0)
2
+(5−y)
2
=(−4−0)
2
+(3−y)
2
36+25−10y+y
2
=16+9−6y+y
2
61−10y+25−6y
61−25=−6y+10y
36=4y
or y=9
The required point is (0,9).
Step-by-step explanation:
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Hi Pragati H R U
what are u doing
Actually I am study for my exam of half early they will going to began that's why