Answer:
Let point P(0,y) is on the y-axis, then
PA=PB
or PA
2
=PB
(6−0)
+(5−y)
=(−4−0)
+(3−y)
36+25−10y+y
=16+9−6y+y
61−10y+25−6y
61−25=−6y+10y
36=4y
or y=9
The required point is (0,9).
Step-by-step explanation:
COORDINATE GEOMETRY
Find the distance between the points the. "A (a+b, a-b) and B(a-b₁-a-b)
2. Find point on y-axis which is equidistant from A (6,5) and B(-4,3). a
me too good Unnie
missed you soo much Unnie
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Verified answer
Answer:
Let point P(0,y) is on the y-axis, then
PA=PB
or PA
2
=PB
2
(6−0)
2
+(5−y)
2
=(−4−0)
2
+(3−y)
2
36+25−10y+y
2
=16+9−6y+y
2
61−10y+25−6y
61−25=−6y+10y
36=4y
or y=9
The required point is (0,9).
Step-by-step explanation:
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Answer:
COORDINATE GEOMETRY
Find the distance between the points the. "A (a+b, a-b) and B(a-b₁-a-b)
2. Find point on y-axis which is equidistant from A (6,5) and B(-4,3). a
Step-by-step explanation:
me too good Unnie
missed you soo much Unnie