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NO SPAMMERS..
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here is your answer
hope it will help you
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We know the logarithmic rules:
1 ) log aⁿ = n log a
2 ) log a ( base a ) = 1
3 ) log ab = log a + log b
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Let log 12 = a ---( 1 )
log 96 log 24 - log 192 log 12
= log(8× 12)log(2 ×12)- log(16×12)log12
= (log8+log12)(log2+log 12)-(log16+log12)log12
= (log2³ + a)(log2+a)-(log2⁴+a)a
= (3log2+a)(log2+a) - (4log2+a)a
= (3+a )( 1 + a ) - ( 4 + a ) a
= 3 + 3a + a + a² - ( 4a + a² )
= 3 + 4a + a² - 4a - a²
= 3
I hope this helps you.
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