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aarchi82
@aarchi82
August 2021
2
7
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construct it on the notebook please
Answers & Comments
PrashantRai2810
Steps of construction:-
1. draw a line segment BC of 6cm.
2.Consruct an angle of 45° on point B and C respectively.
3.mark the point A where these angles intersect.
(the triangle ABC with AB =BC and angle A=90° is formed.)
4.draw an acute angle from point B downwards and divide the arm in 5 units.
5. now join the point a5 to C
6 from point a4 draw a parallel line to intersect BC at C'
7.now from point C' draw a line parallel to AC to intersect AB at C'
the triangle A'BC' is the required triangle which has all the sides equal to 4/5 of the triangle ABC.
hope this will help you
mark it brainliest
©prashantrai
0 votes
Thanks 2
PrashantRai2810
archi my answer is better and clear read and to understand
PrashantRai2810
you should mark my answer as brainliest
khushigarg1703
Aarchi please mark my answer as a brainliest....
0 votes
Thanks 1
khushigarg1703
please mark my answer as brainliest aarchi
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Answers & Comments
1. draw a line segment BC of 6cm.
2.Consruct an angle of 45° on point B and C respectively.
3.mark the point A where these angles intersect.
(the triangle ABC with AB =BC and angle A=90° is formed.)
4.draw an acute angle from point B downwards and divide the arm in 5 units.
5. now join the point a5 to C
6 from point a4 draw a parallel line to intersect BC at C'
7.now from point C' draw a line parallel to AC to intersect AB at C'
the triangle A'BC' is the required triangle which has all the sides equal to 4/5 of the triangle ABC.
hope this will help you
mark it brainliest
©prashantrai