Construct a ∆ABC, in which: AB = 4.5 cm, BC = 7cm and Angle B = 45°.
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Answer:
Draw a line segment BC = 7 cm. Draw the perpendicular bisector of BC, and mark the intersecting point on BC as D. Now draw an arc of radii 4 cm on the constructed bisector, with centre D. Draw an arc of radii 4.5 cm with centre B, which intersects the previous arc at A.
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Answer: Draw a line segment BC = 4.5 cm. 2. Construct ∠CBX = 45°. 3. Set off BP = 8 cm. 4. Join PC. 5. Draw the right bisector of PC, meeting BP at A. 6. Join AC. Thus, ABC is the required triangle. Justification: In APC, ∠ A C P = ∠ A P C
Step-by-step explanation: