Compute the (i) distance travelled and (ii) displacement made by
the student when he travels a distance of 4km eastwards and
then a further distance of 3 km northwards.
the student when he travels a distance of 4km eastwards and
then a further distance of 3 km northwards.
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distance travelled = 4+3 = 7Km.
displacement = shortest distance between two points
= √(4²+3²)
= √25
= 5Km.
Wish It Helps ^_^
(i) The distance travelled = 4+3 = 7 km.
(ii) Displacement refers to the shortest distance between the initial and the final point.
so displacement by Pythagoras theorem:
= √(4)sq.+(3) sq.
= √16+9
= √25
= 5 km
Hope this helped u...