complete the table of the values for x and y using the inequality y<x²+3x+2.
with solution po, please pakisagot na po kailangan na talaga to bukas
with solution po, please pakisagot na po kailangan na talaga to bukas
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Answer:
12, 6, 2, 0, 0, 2, 6
Step-by-step explanation:
1. y < x²+3×+2
-5 < -5²+3(-5)+2
-5 < 25-15+2
-5 < 25-13
-5 < 12
2. y < x²+3x+2
-4 < -4²+3(-4)+2
-4 < 16-12+2
-4 < 16-10
-4 < 6
3. y < x²+3x+2
-3 < -3²+3(-3)+2
-3 < 9-9+2
-3 < 9-7
-3 < 2
4. y < x²+3x+2
-2 < -2²+3(-2)+2
-2 < 4-6+2
-2 < 4-4
-2 < 0
5. y < x²+3x+2
-1 < -1²+3(-1)+2
-1 < 1-3+2
-1 < 1-1
-1 < 0
6. y < x²+3x+2
0 < 0²+3(0)+2
0 < 0+0+2
0 < 2
7. y < x²+3x+2
1 < 1²+3(1)+2
1 < 1+3+2
1 < 6
(kapagod pala magtype HAHAH)