Answer:

1. 14 atm

2. 225 mmHg

3. 120 cm³

4. 5 bar

5. 157.95 L

Step-by-step explanation:

We just have to use Boyle's law. Using the formula P2 = P1 ×V1/V2 where P2 is the final pressure, P1 is the initial pressure, V2 is the final volume, and V1 is the initial volume. After that, we just substitute from the given from each numbers.

1.

Cancel 5mL and 2.5mL, leaving us with 2.

Simplify.

2. 542mmHg = (154L × x)/63.93L

(154L × x)/63.93L = 542mmHg

x/63.93 = 542mmHg/154L

x = (542mmHg × 63.93L)/154L

x = 225.00038961 ≈ 225mmHg

3. 1025879Pa = (x × 586795Pa)/68.64cm³

(x × 586795Pa)/68.64cm³ = 1025879Pa

x/68.64cm³ = 1025879Pa/586795Pa

x = (1025879Pa × 68.64cm³)/586795Pa

x = 120.00159265cm³ ≈ 120cm³

4. x = (2bar × 317mL)/126.8mL

x = 5bar

5. 156Torr = (110Torr × 224L)/x

(110Torr × 224L)/x = 156Torr

224L/x = 156Torr/110Torr

1/x = 156Torr/(224L × 110Torr)

1 = (156Torr × x)/(224L × 110Torr)

x = 157.94871794... ≈ 157.95L

Here's the answer just click the pic hope it helps