Step-by-step explanation:
For graphing, I like using the slope-intercept form, where the general form is
y=mx+b, where m is the slope and b is the y-intercept.
To get there, solve for y:
3x−4y=−8
−4y=−3x−8
y=34x+2
We now have a form where we can pick out the y-intercept (the point (0,2). We can use the slope to find another point to plot.
Slope=riserun and so we can add 3 to the y value for every 4 we add to the x value:
(0+4,2+3)=(4,5)
We now have to points so we can graph the line:
graph{((x-0)^2+(y-2)^2-.1)((x-4)^2+(y-5)^2-.1)(3x-4y+8)=0[-15,15,-7,7]}
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Answers & Comments
Step-by-step explanation:
For graphing, I like using the slope-intercept form, where the general form is
y=mx+b, where m is the slope and b is the y-intercept.
To get there, solve for y:
3x−4y=−8
−4y=−3x−8
y=34x+2
We now have a form where we can pick out the y-intercept (the point (0,2). We can use the slope to find another point to plot.
Slope=riserun and so we can add 3 to the y value for every 4 we add to the x value:
(0+4,2+3)=(4,5)
We now have to points so we can graph the line:
graph{((x-0)^2+(y-2)^2-.1)((x-4)^2+(y-5)^2-.1)(3x-4y+8)=0[-15,15,-7,7]}