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The girl needs to buy 8 packs of coloured pencils and 3 packs of crayons in market.

Given :

• Coloured pencils are available in market in packs of 12 each and crayons in pack of 32 each.

• A girl wants full pack of both and the same number of pencils and crayons

To find :

Number of packs of coloured pencils and of crayons the girl needs to buy in market

Solution :

Step 1 of 3 :

Write down number of coloured pencils and crayons in each pack

Here it is given that coloured pencils are available in market in packs of 12 each and crayons in pack of 32 each.

Number of coloured pencils in each pack = 12

Number of crayons in each pack = 32

Step 2 of 3 :

Calculate LCM of 12 and 32

12 = 2 × 2 × 3

32 = 2 × 2 × 2 × 2 × 2

∴ LCM of 12 and 32

= 2 × 2 × 2 × 2 × 2 × 3

= 96

Step 3 of 3 :

Calculate number of packs of coloured pencils and of crayons the girl needs to buy in market

Since LCM of 12 and 32 = 96

The girl needs to buy 96 coloured pencils and 96 crayons in market

Number of pack of coloured pencils

[tex]\displaystyle \sf = \frac{96}{12} [/tex]

[tex]\displaystyle \sf = 8[/tex]

Number of pack of crayons

[tex]\displaystyle \sf = \frac{96}{32 }[/tex]

[tex]\displaystyle \sf = 3[/tex]

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Answer:

Take HCF of 12 and 32

12=2*2*3

32=2*2*2*2*2

HCF=4

Now divide both the no. by 4

32/4=8

12/4=3

so she has to buy 3 packs of pencil and 8 packs of crayons so that she can get same number of pe cils and crayon.