Step-by-step explanation:
we know that length of two sides is greater than the third side
let the triangle be ∆ABC
given AB=10;BC=16
AB+BC =AC
[tex] ab + bc > ac \: or \\ \\ bc - ad < ac \: [/tex]
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Step-by-step explanation:
we know that length of two sides is greater than the third side
let the triangle be ∆ABC
given AB=10;BC=16
AB+BC =AC
[tex] ab + bc > ac \: or \\ \\ bc - ad < ac \: [/tex]