Given, AD= 4 cm
BD= 3cm
CB= 12cm
ADB=90°
angle ABC= 90°
To find, cot
So, first let's find the value of AB.
We know that ADB is a right angle.
So, AB can be found by Pythagoras theorem.
By Pythagoras theorem
ABC= 90°
,
is the angle, then,
opposite=AB=5 cm
adjescent=BC=12 cm
hypotenuse=AC=13 cm
But we know,
To find,
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Answers & Comments
AD=4cm
BD=3cm
CB=12cm
Angle C=theta
AB^2=AD^2+BD^2
=4^2+3^2
=16+9
=25
AB=
AB=5cm
So, cot theta=AB/CB
=5/12
Given, AD= 4 cm
BD= 3cm
CB= 12cm
angle ABC= 90°
To find, cot![\theta \theta](https://tex.z-dn.net/?f=%5Ctheta)
So, first let's find the value of AB.
We know that
ADB is a right angle.
So, AB can be found by Pythagoras theorem.
By Pythagoras theorem
,![AC^2=AB^2+BC^2\\ AC^2=(5)^2+(12)^2\\ AC^2=25+144\\ AC^2=169\\ \therefore AC=13 cm\\ >. </p><p>We know, </p><p><img src=](https://tex.z-dn.net/?f=AC%5E2%3DAB%5E2%2BBC%5E2%5C%5C%20AC%5E2%3D%285%29%5E2%2B%2812%29%5E2%5C%5C%20AC%5E2%3D25%2B144%5C%5C%20AC%5E2%3D169%5C%5C%20%5Ctherefore%20AC%3D13%20cm%5C%5C)
opposite=AB=5 cm
adjescent=BC=12 cm
hypotenuse=AC=13 cm
But we know,![sin\theta=\frac{opposite}{hypotenuse}\\ \\ cos\theta=\frac{adjescent}{hypotenuse}\\ \\ sin\theta=\frac{opposite}{hypotenuse}\\ \\ cos\theta=\frac{adjescent}{hypotenuse}\\ \\](https://tex.z-dn.net/?f=sin%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%5C%5C%20%5C%5C%20cos%5Ctheta%3D%5Cfrac%7Badjescent%7D%7Bhypotenuse%7D%5C%5C%20%5C%5C%20)
To find,