Class 10 CBSE Subject- Math Ch 3 Pair of Linerar Equation in two variables. pg 57 Ex. 3.4 Qn 2 ii)
Pls help me with this question.Incomplete answer will be reported. Give answer with explanation.If u don't know don't answer or else I will report.
Pls help me with this question.Incomplete answer will be reported. Give answer with explanation.If u don't know don't answer or else I will report.
Answers & Comments
As per the question.
Let the present age of Nuri = x years
Let the present age of Sonu = y years
Five years ago,
Age of Nuri = (x-5) years
Age of Sonu = (y-5) years
As already given that,
Age of Nuri = 3(Age of Sonu)
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y = -10 ------(1)
Ten years hence,
Age of Nuri = (x + 10) years
Age of Sonu = (y + 10) years
Age of Nuri will be twice as Sonu.
x + 10 = 2(y + 10)
x - 2y = 10 ------(2)
From using equation (1) and (2), we get.
x - 3y = -10
x - 2y = 10
(-) (+) = (-)
___________
-y = -20
y = 20 years
Putting the value of "y" in equation (2)
x - 2(20) = 10
x = 50 years.
Hence,
The present age of Nuri = x = 50 years.
The present age of Sonu = y = 20 years.