Let's denote the circumference of the fore wheel as \(2n\) meters and the circumference of the rear wheel as \(3r\) meters.

If the fore wheel makes 10 more rotations than the rear wheel, the distance covered by the car is equal to the circumference of the fore wheel multiplied by the number of rotations it made. The distance covered by the rear wheel is similarly the circumference of the rear wheel multiplied by the number of rotations it made.

Let \(x\) be the number of rotations made by the rear wheel. Then, the fore wheel made \(x + 10\) rotations.

The distance covered by the car is given by the sum of the distances covered by the fore and rear wheels:

\[Distance = (2n) \times (x + 10) + (3r) \times x\]

Simplify this expression to find the total distance covered by the car.