Answer:
2.Therefore,Molality=1040901000=1040×100090=2.778
4.As given, of 20% glucose solution. Therefore,the required the mass of glucose =200 g. Thus,the required mass of glucose to prepare 1dm3 of 20% glucose. solution is 200 gram
5. Molality and mole fraction are independent of temperature.
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Answers & Comments
Answer:
2.Therefore,Molality=1040901000=1040×100090=2.778
4.As given, of 20% glucose solution. Therefore,the required the mass of glucose =200 g. Thus,the required mass of glucose to prepare 1dm3 of 20% glucose. solution is 200 gram
5. Molality and mole fraction are independent of temperature.