Check whether the following are solutions of the system
2x + y = -3 and x - 3y = -5 then graph:
a.) (-2, 1)
b.) (2, -5)
solve the system of linear equations by graphing. use table of values
a.) x + y = 6 and 3x - y = -2
b.) y = 2x + 3 and y = 4x + 1
c.) -x + y = -4 and -2x + y = -6
pasagot po pls huhu tyy
2x + y = -3 and x - 3y = -5 then graph:
a.) (-2, 1)
b.) (2, -5)
solve the system of linear equations by graphing. use table of values
a.) x + y = 6 and 3x - y = -2
b.) y = 2x + 3 and y = 4x + 1
c.) -x + y = -4 and -2x + y = -6
pasagot po pls huhu tyy
Answers & Comments
Answer:
A.1.) 2x + y = -3
a.) y = -2x - 3
when x = -2
y = -2(-2) - 3
y = 4 - 3
y = 1
Therefore, (-2, 1) is a solution to the system.
b.) y = -2x - 3
when x = 2
y = -2(2) - 3
y = -4 - 3
y = -7
Therefore, (2, -5) is not a solution to the system.
Table:
x -2 -1 0 1 2
y 1 -1 -3 -5 -7
A.2.) x - 3y = -5
a.) 3y = x + 5
y = ⅓(x + 5)
when x = -2
y = ⅓(-2 + 5)
y = ⅓(3)
y = 1
Therefore, (-2, 1) is a solution to the system.
b.) 3y = x + 5
y = ⅓(x + 5)
when x = 2
y = ⅓(2 + 5)
y = ⅓(7)
y = ⁷⁄₃
Therefore, (2, -5) is not a solution to the system.
Table:
x -2 -1 0 1 2
y 1 ⁴⁄₃ ⁵⁄₃ 2 ⁷⁄₃
II. a) x + y = 6
y = 6 - x
Table:
x -2 -1 0 1 2
y 8 7 6 5 4
3x - y = -2
y = 3x + 2
Table:
x -2 -1 0 1 2
y -4 -1 2 5 8
b.) y = 2x + 3
Table:
x -2 -1 0 1 2
y -1 1 3 5 7
y = 4x + 1
Table:
x -2 -1 0 1 2
y -7 -3 1 5 9
c.) -x + y = -4
y = x - 4
Table:
x -2 -1 0 1 2
y -6 -5 -4 -3 -2
-2x + y = -6
y = 2x - 6
Table:
x -2 -1 0 1 2
y -10 -8 -6 -4 -2
See the attachments for the graphs.