Answer:

if any digit has the last digit 0 that means it will divisible by 10.

the factors of 10=2×5

so the value of 6^n should be divisible by 2 and 5.

both 6^n is divisible by 2 but not with 5.

so,it cannot be end with 0.

Step-by-step explanation:

It can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.