Answer:
1. 2x²-3x+4=0
2.7r²-14r+17=0
3.b²+2b-35=0
4.8x²+59x+21=0
5.x²+18x+56=0
Step-by-step explanation:
[tex]1.) \: \: 2 {x}^{2} = 3x - 4 \\ 2 {x}^{2}( - 3x + 4) = 3x - 4 \: ( - 3x + 4) \\ 2 {x}^{2} - 3x + 4 = 0[/tex]
[tex]2.)7{r}^{2} - 14r = - 17 \\ 7 {r}^{2} - 14r + 17 = - 17 + 17 \\ 7 {r}^{2} - 14r + 17 = 0[/tex]
[tex]3.) {b}^{2} + 5b - 35 = 3b \\ {b}^{2} + 5b - 3b - 35 = 3b - 3b \\ {b}^{2} + 2b - 35 = 0[/tex]
[tex]4.)8 {x}^{2} + 21 = - 59x \\ 8 {x}^{2} + 59x + 21 = - 59x + 59x \\ 8 {x}^{2} + 59x + 21 = 0[/tex]
[tex] 5.){x}^{2} + 18x + 81 = 25 \\ {x}^{2} + 18x + 81 - 25 = 25 - 25 \\ {x}^{2} + 18x + 56 = 0[/tex]
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Verified answer
Answer:
1. 2x²-3x+4=0
2.7r²-14r+17=0
3.b²+2b-35=0
4.8x²+59x+21=0
5.x²+18x+56=0
Step-by-step explanation:
[tex]1.) \: \: 2 {x}^{2} = 3x - 4 \\ 2 {x}^{2}( - 3x + 4) = 3x - 4 \: ( - 3x + 4) \\ 2 {x}^{2} - 3x + 4 = 0[/tex]
[tex]2.)7{r}^{2} - 14r = - 17 \\ 7 {r}^{2} - 14r + 17 = - 17 + 17 \\ 7 {r}^{2} - 14r + 17 = 0[/tex]
[tex]3.) {b}^{2} + 5b - 35 = 3b \\ {b}^{2} + 5b - 3b - 35 = 3b - 3b \\ {b}^{2} + 2b - 35 = 0[/tex]
[tex]4.)8 {x}^{2} + 21 = - 59x \\ 8 {x}^{2} + 59x + 21 = - 59x + 59x \\ 8 {x}^{2} + 59x + 21 = 0[/tex]
[tex] 5.){x}^{2} + 18x + 81 = 25 \\ {x}^{2} + 18x + 81 - 25 = 25 - 25 \\ {x}^{2} + 18x + 56 = 0[/tex]