Answer:

1. 1/3

2.1/6

3.1/6

4.1/2

5.12

Explanation:

1.Hence, the probability of getting a multiple of 3 when a die is thrown is 1/3.

2.Hi friend , hence probability of any one outcome occurring = 1/6 . The event that we get that an even number on tossing the die can occur in 3 possible ways .

3.For each of the possible outcomes add the numbers on the two diceand count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7is 6/36 = 1/6

4.Hence, the required probability of getting an odd number , P(E) = 1/2

5.We can see from the above steps that the number of favourable outcomes where we get a prime number is 3 and the total number of possible outcomes i.e. the number of elements in the sample space is 6. Hence, the probability of getting a prime number is 12. This is our final answer.

Hehe