Answer:
Carbon and oxygen react in the ratio 3:8 by mass to form Carbon dioxide.
hence the required reaction is;
C+O2--> CO2
carbon: oxygen = 3:8
due to law of constant proportion , the mass ratio in which the reactants react will remain constant .
Carbon -> 9 g
Oxygen-> ?
C:O2-> 3:8
9:O2-> 3:8
9\O2 = 3\8
Mass of required oxygen
(9\3)×8
3×8
24 g
Carbon->9 g
Oxygen->24 g
hope it will help you
It is given that,
It is given that,C + O2 ---> CO2
in carbon dioxide, the ratio of mass of carbon to oxygen is 3 : 8.
Let x grams be the mass of the oxygen that would be required to react completely with 6 grams of carbon. According to the law of constant proportion,
(6/x) = (3/8)
=> x = 16 g
Therefore, 16g of oxygen is required to completely react with 6 gram of carbon.
Since you now know the reaction for the formation of CO2, work on it yourself and let us know if you face any issues.
Thanks,
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Answers & Comments
Answer:
Carbon and oxygen react in the ratio 3:8 by mass to form Carbon dioxide.
hence the required reaction is;
C+O2--> CO2
carbon: oxygen = 3:8
due to law of constant proportion , the mass ratio in which the reactants react will remain constant .
Carbon -> 9 g
Oxygen-> ?
C:O2-> 3:8
9:O2-> 3:8
9\O2 = 3\8
Mass of required oxygen
(9\3)×8
3×8
24 g
Carbon->9 g
Oxygen->24 g
hope it will help you
It is given that,
It is given that,C + O2 ---> CO2
in carbon dioxide, the ratio of mass of carbon to oxygen is 3 : 8.
Let x grams be the mass of the oxygen that would be required to react completely with 6 grams of carbon. According to the law of constant proportion,
(6/x) = (3/8)
=> x = 16 g
Therefore, 16g of oxygen is required to completely react with 6 gram of carbon.
Since you now know the reaction for the formation of CO2, work on it yourself and let us know if you face any issues.
Thanks,