Step-by-step explanation:

Let the points A (1,5) B (5, 8) and C (13, 14)

Register

Distance of AB

AB=√((5-1)² + (8-5)²)

AB=√((4)² + (3)²)

AB=√(16+9)

AB = sqrt(25)

AB = 5

Distance of BC

⇒ BC = √((13-5)²+(14-8)²)

⇒BC=√((8)² + (6)²)

→ BC= √ (64+36)

BC = sqrt(100)

BC = 10

Distance of AC

⇒ AC=√((13 - 1)²+(14-5)²)

⇒ AC=√((12)² + (9)²)

⇒ AC = √ (144 +81)

⇒ AC = sqrt(225)

AC = 15

Now, we can see that AB + BC = AC.

A, B and C are collinear. Hence, we cannot draw triangle using these coordinates.

Answer:

15,AC is answer please make me brainslit