[tex]\huge\mathcal{\fcolorbox{yellow} {beige} {\orange{Solution}}}[/tex]
Given : in Fig two straight lines AB and CD intersect at O ∠COT = 60°
To find : a , b & c
Solution:
AB is a straight line
Hence
4b + 60° + b = 180°
=> 5b = 120°
=> b = 24°
CD is a straight line
60° + b + a = 180°
=> b + a = 120°
=> 24° + a = 120°
=> a = 96°
4b + 2c = 180°
=> 4(24) + 2c = 180°
=> 96° + 2c = 180°
=> 2c = 84°
=> c = 42°
a = 96° , b = 24° , c = 42°
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[tex]\bold{Thank ~you~:)}[/tex]
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[tex]\huge\mathcal{\fcolorbox{yellow} {beige} {\orange{Solution}}}[/tex]
Given : in Fig two straight lines AB and CD intersect at O ∠COT = 60°
To find : a , b & c
Solution:
AB is a straight line
Hence
4b + 60° + b = 180°
=> 5b = 120°
=> b = 24°
CD is a straight line
60° + b + a = 180°
=> b + a = 120°
=> 24° + a = 120°
=> a = 96°
4b + 2c = 180°
=> 4(24) + 2c = 180°
=> 96° + 2c = 180°
=> 2c = 84°
=> c = 42°
a = 96° , b = 24° , c = 42°
[tex]{\color{gold}{\underline{\rule{100pt}{0pt}}}}{\color{hotpink}{\underline{\rule{100pt}{0pt}}}}[/tex]
[tex]\bold{Thank ~you~:)}[/tex]