shivansh60
Let the speed of the goods train be xm/s then speed of the express train =x+39×5/18 ms time taken by express train is t sec time taken by the goods train be t+36×60=t+2160 sec we know, x+65/6=180/t t=180/X+65/6. -----(i) distance=speed×time for the goods train,. 180=x(t+2160) for express train,. 180=(X+65/6)t from above,x(t+2160)=(x+65/6)t onsolving,. t=2592x/13 using (i),. 180/x+65/6=2592x/13 on solving,. you will get the answer.
Answers & Comments
then speed of the express train =x+39×5/18 ms
time taken by express train is t sec
time taken by the goods train be t+36×60=t+2160 sec
we know, x+65/6=180/t
t=180/X+65/6. -----(i)
distance=speed×time
for the goods train,. 180=x(t+2160)
for express train,. 180=(X+65/6)t
from above,x(t+2160)=(x+65/6)t
onsolving,. t=2592x/13
using (i),. 180/x+65/6=2592x/13
on solving,. you will get the answer.