θ = 60°,0°
Step-by-step explanation:
Given Equation is (cos²θ - 3cosθ + 2)/sin²θ = 1
⇒ cos²θ - 3cosθ + 2 = sin²θ
⇒ cos²θ - 3cosθ + 2 = (1 - cos²θ)
⇒ cos²θ - 3cosθ + 2 - 1 + cos²θ = 0
⇒ 2cos²θ - 3cosθ + 1 = 0
⇒ 2cos²θ - 2cosθ - cosθ + 1 = 0
⇒ 2cosθ(cosθ - 1) - (cosθ - 1) = 0
⇒ (2cosθ - 1)(cosθ - 1) = 0
⇒ cosθ = (1/2) (or) cosθ = 1
⇒ θ = 60° (or) 0°
I HOPE THIS ANSWER IS HELPFUL FOR YOU,........
THANKS
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θ = 60°,0°
Step-by-step explanation:
Given Equation is (cos²θ - 3cosθ + 2)/sin²θ = 1
⇒ cos²θ - 3cosθ + 2 = sin²θ
⇒ cos²θ - 3cosθ + 2 = (1 - cos²θ)
⇒ cos²θ - 3cosθ + 2 - 1 + cos²θ = 0
⇒ 2cos²θ - 3cosθ + 1 = 0
⇒ 2cos²θ - 2cosθ - cosθ + 1 = 0
⇒ 2cosθ(cosθ - 1) - (cosθ - 1) = 0
⇒ (2cosθ - 1)(cosθ - 1) = 0
⇒ cosθ = (1/2) (or) cosθ = 1
⇒ θ = 60° (or) 0°
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Step-by-step explanation:
I HOPE THIS ANSWER IS HELPFUL FOR YOU,........
THANKS