step-by-step expalination:
we gonna use the following equation
cos2θ = 2cos²θ - 1 (a)
cos2θ + 1 = 2cos²θ (b)
we can write the question as 4cos²θ - 1 using the
(a+b)(a-b) theorem
4cos²θ - 1
=2cos²θ + 2cos²θ - 1
i am gonna substitute the equation (a) for 2cos²θ - 1
and equation (b) for 2cos²θ
=cos2θ + 1 + cos2θ
=2cosθ + 1
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Verified answer
step-by-step expalination:
we gonna use the following equation
cos2θ = 2cos²θ - 1 (a)
cos2θ + 1 = 2cos²θ (b)
we can write the question as 4cos²θ - 1 using the
(a+b)(a-b) theorem
4cos²θ - 1
=2cos²θ + 2cos²θ - 1
i am gonna substitute the equation (a) for 2cos²θ - 1
and equation (b) for 2cos²θ
=cos2θ + 1 + cos2θ
=2cosθ + 1